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X^2+X^2-18X-40=0
We add all the numbers together, and all the variables
2X^2-18X-40=0
a = 2; b = -18; c = -40;
Δ = b2-4ac
Δ = -182-4·2·(-40)
Δ = 644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{644}=\sqrt{4*161}=\sqrt{4}*\sqrt{161}=2\sqrt{161}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{161}}{2*2}=\frac{18-2\sqrt{161}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{161}}{2*2}=\frac{18+2\sqrt{161}}{4} $
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